Re: [igraph] Cannot convert directed graph into undirected graph using python

[Gábor Csárdi]

On Sat, Feb 22, 2014 at 1:20 AM, Salvatore Palomino <address@hidden> wrote:

Because the purpose of the function is to convert g into and undirected graph.

And it does just that.

 

Also, when I use other functions that perform operations on graphs, they always return the graph. Thus, its logical that it would return g and not None. 

No, they don't. They modify the graph in place and return None. E.g.:

>>> g=igraph.Graph()

>>> a=g.add_vertices(3)

>>> print a

None

>>> b=g.add_edges([(0,1), (1,2)])

>>> print b

None

Gabor

 

 

On Fri, Feb 21, 2014 at 5:15 PM, Gábor Csárdi <address@hidden> wrote:

On Fri, Feb 21, 2014 at 8:10 PM, Salvatore Palomino <address@hidden> wrote:

i think it should return g as an undirected graph. Instead it returns "None" 

Why should it return the graph?

Gabor

 

On Fri, Feb 21, 2014 at 4:07 PM, Gábor Csárdi <address@hidden> wrote:

On Fri, Feb 21, 2014 at 6:55 PM, Salvatore Palomino <address@hidden> wrote:

Hello!

I am trying to convert my directed graph g into an undirected graph using to_undirected().

<< g = GraphBase.Read_Pajek("C:/Users/Palomino/Downloads/109Senate-Rows.net")

<< g = g.to_undirected(False)

<< print g

None

I don't know why it returns None. Can you help me out?

What should it return? The result of the conversion is in g, it does it in place.

G.

 

 

Thanks!!!

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