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Re: browsing repository modules
From: |
Jasper V Ferrer |
Subject: |
Re: browsing repository modules |
Date: |
Tue, 24 Apr 2001 20:34:46 -0800 |
thank you, just what i needed.
i can now see the projects in my repository, i also got more than what i am
looking for.
i setup my modules file like this:
cb -s C++-REVIEW constbhvr
td -s QT tdialog
now cvs co -s produces:
cb C++-REVIEW constbhvr
td QT tdialog
what i want though is a way put in some comments and its current version (not
the branch). i used the status to categorise my modules. so "td QT tdialog"
belongs of my Qt projects.
to have comments i experimented with the modules file, and my changes looks
like:
# Key Category Module Remarks
cb -s C++-REVIEW constbhvr # shows behaviour of const when
used with pointers. [0.1]
td -s QT tdialog # a simple dialog-based app. [0.1]
when i checked my repository, heres what i got:
$ cvs co -s
cb C++-REVIEW constbhvr
# shows behaviour of const when used with pointers.
[0.1]
td QT tdialog
# a simple dialog-based app. [0.1]
the row header comment "# Key Category..." is just to explain how i use the
-s option, the number n.n inside the square brackets reflects the current
version. as you can see, the output of is exactly what i wanted (though i wish
the comments appear on the same line). is this behaviour expected? if this is
a bug, i hope it remains that way :)
many thanks to peter too.
Matthias Kranz wrote:
>On Mon, Apr 23, 2001 at 06:43:06PM -0800, Jasper V Ferrer wrote:
>> is there any way i can determine what modules are stored in the
>> repository? currently i just have a log file where i note the
>> modules (projects) i have imported and their corresponding branches
>> and some description of the project.
>
>If you are using the CVSROOT/modules file, you could do it via
>
> cvs co -c
>
>See
>
> http://www.cvshome.org/docs/manual/cvs_18.html#SEC155
> http://www.cvshome.org/docs/manual/cvs_16.html#SEC122
>
>for more details.
>
>Cheers,
>Matthias
>--
>Matthias Kranz address@hidden
> http://www.belug.org/~kranz
>ech`echo xiun|tr nu oc|sed 'sx\([sx]\)\([xoi]\)xo un\2\1 is xg'`ol
>
>
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