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| From: | Michael Käppler |
| Subject: | Re: [PATCH] Completion_heads_engraver broken? |
| Date: | Fri, 27 Feb 2009 17:13:13 +0100 |
| User-agent: | Thunderbird 2.0.0.12 (X11/20071114) |
moment I can't imagine cases where this could happen.Can't happen, AFAICT: by the definition of k, k >= -intlog2(p) and so -k <= intlog2(p) <= log2(p). Therefore 2^{-k} <= p and so (p >> -k) == p*2^k >= 1. That is, you never shift everything away.
Ok, so what's the next step now?
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