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Re: barcheck
From: |
David Bobroff |
Subject: |
Re: barcheck |
Date: |
Thu, 10 Oct 2002 18:50:05 +0000 |
At 06:30 PM 10/10/2002 +0200, you wrote:
>David Bobroff wrote:
>
>> \time 3/4
>...
>> \cadenzaOff
>> \property Staff.fontSize = #0
>> f8.-\trill( es32 )f | es4 r r |
>
>The 1st measure after cadenzaOff is only 1/2 (1.5/8+1/32+1/32) and not
>3/4 - and hence you DO have a bar check failure. What did you expect?
>
>-Rune
Actually, what I expected was that after the beginning of the \cadenzaOn
time would not be counted until after \cadenzaOff. Immediately before the
\cadanzaOn is a half-note. Then the cadenza and then a quarter (dotted 8th
+ 2 32nds) which makes 3/4. It worked earlier when I did this:
%%%%%%%%%%%%%
\score{
\notes \relative c'{
\clef F
\key es \major
\time 4/4
bes4-\fermata
\cadenzaOn
\property Staff.fontSize = #-2
\times 2/3 {f8 bes d,} \times 2/3 {f bes, d } \times 2/3 {f, bes d,}
\bar "" \break
f4 r8 g4 f e8 f16-. f'( e )f f,-. es'( d )es f,-. d'( cis )d f,-. c'(
b )c
g'-. f,( e ) f f'-. g,( f )g es'-. a,( g )a [d-. bes( a )bes] \bar ""
\break
\property Score.beatLength = #(make-moment 1 8)
[\times 2/3 {es16 f g} \times 2/3 {f es d} ]
[\times 2/3 { c16 d es } \times2/3 {d c bes}]
\property Score.beatLength = #(make-moment 1 4) [a16. c32 f16. a32] c16
r
es,8
\property Score.beatLength = #(make-moment 1 8)
[\times 2/3 {d16 es g} \times 2/3 {es d c} ]
[\times 2/3 {bes c d} \times 2/3 {c bes a}]
\property Score.beatLength = #(make-moment 1 4)
[g16. bes32 es16. g32] bes16 r e,,8
\bar "" \break
\property Score.beatLength = #(make-moment 1 8)
[\times 2/3 {[f16-. bes( )a} \times 2/3 {bes-. g-. e-.}] [ \times 2/3
{f-.
bes( ) a} \times 2/3{ bes-. g-. e-.}]
[f16 -. g32-. a-. bes-. c-. d-. e-.]
\property Score.beatLength = #(make-moment 1 4)
f16-. g-. a-. bes-.
\cadenzaOff
c4 \property Staff.fontSize = #0
a8.-\trill( g32 )a bes4 r | R1*3 | R1*2 | \bar "|."
}
}
%%%%%%%%%%%%%%%
In this example the \cadenzaOn/Off appeared to simply turn off any time
count during the cadenza and turned it back on when I asked it to in order
to complete the "count" of the measure. What have I done differently in
this example that makes it work?
-David Bobroff
- barcheck, David Bobroff, 2002/10/10
- Re: barcheck, Rune Zedeler, 2002/10/10
- Re: barcheck,
David Bobroff <=