Re: A question on "##t"

[Graham Percival]

Folks, the new LM is designed **exactly** to clarify this kind of
thing.  Please take a look at that; if it's unclear, then let's
fix it once in the docs, instead of discussing it on -user every
six months.

I think the exact section is LM 4.2.3, but you should probably
skim through LM 3 and the beginning of LM 4 before you look at
that.

Cheers,
- Graham

On Thu, 24 Jan 2008 20:13:25 +0000
Damian leGassick <address@hidden> wrote:

> actually, this confuses me too
> 
> if the # puts lilypond into scheme mode, does that mean that the  
> equals-sign in #'merge-differently-headed = ##t  is not scheme? if
> it is, then why not #'merge-differently-headed = #t  ?
> 
> d
> 
> 
> On 24 Jan 2008, at 16:06, Mats Bengtsson wrote:
> 
> >
> >
> > Martin Seng Hin Yew wrote:
> >> Bertalan Fodor (LilyPondTool) wrote:
> >>> Everything beginning with a # is a Scheme-language expression.
> >>> So this sets the property called 'merge-differently-headed to
> >>> the value #t
> >>> #t is the expression meaning true in Scheme.
> >>>
> >> Hi Bertalan Fodor,
> >>
> >> Okay...assume i knew the word "true" (means =yes or 1, right?),  
> >> but ##t got double #, so what does the other # means?
> > He already told you :-) The first # tells LilyPond that "here
> > comes a Scheme
> > expression", the "#t" which follows is the actual Scheme code.
> >
> >   /Mats
> >
> >
> > _______________________________________________
> > lilypond-user mailing list
> > address@hidden
> > http://lists.gnu.org/mailman/listinfo/lilypond-user
> 
> 
> 
> _______________________________________________
> lilypond-user mailing list
> address@hidden
> http://lists.gnu.org/mailman/listinfo/lilypond-user