Re: A question on "##t"

[Ralph Little]

> if the # puts lilypond into scheme mode, does that mean that the  
> equals-sign in #'merge-differently-headed = ##t  is not scheme? if
> it is, then why not #'merge-differently-headed = #t  ?

In fairness to Damian, I think his further question was more to 
do with the scope of the # scheme introducer.

i.e. how much of what follows the # is interpreted
as scheme.

I'm not sure that I know the definitive answer to that 
question since you can define an entire scheme function with 
a single # in a different context.
 
In answer to his specific question about 
#['merge-differently-headed = #t], it wouldn't work anyway 
because the syntax of scheme is different. The assignment 
here is Lilypond's syntax.

Regards,
Ralph

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