Re: Beaming sixteenths sandwiched in a triplet

[Matthew Rowles]

That sort of beaming is broken in 2.10.33.

I think that it is fixed in the current dev version... (but I'm yet to
try it out)


2008/7/15 Chris Canipe <address@hidden>:
> I'm struggling in my attempts at beaming two sixteenths in the middle of a
> triplet. Is this possible with automatic beaming, or must one result to beam
> counts?
>
> I've attached an example showing my current output and my desired output;
> code follows:
>
> \paper{ ragged-right=##t }
> \relative c'' {
>     \time 4/4
>     \times 2/3 { c8 c16 c c8 }
>     r4 r r
> }
>
> Thanks!
>
> P.S. I'm using version 2.10.33.
>
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>
>



-- 
Matthew Rowles

- Be Alert. Australia needs lerts.