Re: problem with substitution

[Carl D. Sorensen]

On 12/22/08 2:30 AM, "Stefan Thomas" <address@hidden>
wrote:

> Dear Lilypond-users,
> I trie to substitute the variable "zackigschnell' with "APZ', but
> without sucess.
> What is wrong with the following snippet?

> 
> \version "2.11.60"
> \include "rhythmustest.ly"
> \new Staff { \APZ { c' d' e' f' } }

There's nothing wrong with the snippet.

The problem occurred in rhythmustest.ly.

You had the following:
zackigschnell = #(define-music-function (parser location music) (ly:music?)
#{  \makeRhythm $music "16. 32"  #})
APZ =  { \zackigschnell }

The way LilyPond substitution works, \zackigschnell needs to be followed by
a music expression.  And in your definition of APZ, there is no music
expression following \zackigschnell.  If you literally do the substitution,
you'll get

\new Staff { { \zackigschnell } {c' d' e' f' } }

and you can see that there is no music expression for \zackigschnell to
operator on.

If you literally want to just add a new name for a function, the way to do
it is with a scheme trick.

Simply add 

#(define APZ zackigschnell)

and now APZ and zackigschnell are the same thing with two different names.

I've tried it on your code, and this works.

Good luck,

Carl