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6/8 time triplets problem


From: Chip
Subject: 6/8 time triplets problem
Date: Wed, 25 Feb 2009 20:08:57 -0700
User-agent: Thunderbird 2.0.0.19 (Windows/20081209)

In the following code the triplets do not work properly - there are two measures of quarter note triplets followed by a dotted half note - they all end up in one measure together.
===============================
{
\partial 8*1 e8-.
e4 d8 c4 d8
e4 e8-. r r e
e4 d8 c4 d8
e4 e8 r r fs
g4 fs8 g4 e8
d2 d8 e
\times 2/3 {f4 fs b}
\times 2/3 {d4 c b}
g2.\fermata \bar "||"
R1*5
e,2 e8 g
fs2.
b2.
c2.
r2.*3
r4 r c8 d
e4 d c8 b
g4. a
b c
d2.
r2.*4
e,2 d8 g
fs2.
b2.
c2.
R2.*3
r4 r4 r8 fs,
b2 c8 d
e2.
d4. c4 d8
e2.
R2.*3
R2.*6
R2.*3
r4 r b8 d
fs4 d8~ d[ b g] \bar "||" \key af \major
ef'4 ef8 ef4 ef8
ef8 r r4 r
R2.*6
r4 r r8 c
df4 df8 bf4 af8
bf4 bf8 r bf c
df4 c8 bf4 af8
bf4 r8 ef[ g bf]
c4 c bf8 af
af2.~
af4. r8 r g \bar "||" \key g \major
e2 fs8 g
a2.
R2.*5
e,2 e8 g
fs2.
b2.
c2.
R2.*3
r4 r c8 d
e4 d c8 b
g4. a4.
b4. c4.
d2.
R2.*4
e,2 d8 g
fs2.
b2.
c2.
R2.*3
r4 r4 r8 fs,
b2 c8 d
e2.
d4. c4 d8
e2.
R2.*3
R2.*6
R2.*3
r4 r b8 c
d4 d d8 c
b4. c4.
d4. f4.
e2.
R2.*4
r4 r b8 d
a4 f d8 bf
ef2 bf8 ef
g4. bf4.
a2.\fermata \bar "|."
}
==================================




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