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Re: beatLength and \times n/m {}


From: Urs Liska
Subject: Re: beatLength and \times n/m {}
Date: Tue, 11 Oct 2011 09:35:16 +0200
User-agent: Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.2.23) Gecko/20110922 Lightning/1.0b2 Thunderbird/3.1.15

Am 10.10.2011 21:26, schrieb paul:
I have a little problem with beat length which appears to have
  been discussed in the past, nonetheless I
cannot get the result I want.
I have simple music in 2/4 time and need to display, per 1/4 note,
sextuplets of 1/16 th notes.

Ordinarily this is simple but I would like to have
the six 16th notes appear as three groups of
  two, not one group of 6. I have tried the
  following to no avail

\autoBeamOff
\set subdivideBeams = ##t
\set beatLength = #(ly:make-moment 2 16)
\times 4/6{c16 c c c c d}

Perhaps there is something pedantic about doing this
inside a \times n/m {} construction ?

Apologies if this is a trivial oversight on my part.

Paul

I'm not sure right now if your approach would work in general or if you have to use Nick's version. But in any case the beatLength you'd want is 2/24 and not 2/16. The beatLength works isn't influenced by your \times construct, so you have to use the actual duration.

HTH
Urs

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