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Re: subdividing sixteenth-note triplet beam groups


From: Steve Yegge
Subject: Re: subdividing sixteenth-note triplet beam groups
Date: Sat, 20 Oct 2012 11:36:10 -0400

Nick's works -- thanks Nick!

Wim, your solution doesn't work; not sure why.  It would certainly be simpler if it did.

-steve

On Sat, Oct 20, 2012 at 5:55 AM, Wim van Dommelen <address@hidden> wrote:
And why not very simply:

    \times 2/3 { c16[ c c c c c] }

Regards,
Wim.

On 20 Oct 2012, at 00:15 , Nick Payne wrote:

On 20/10/12 08:58, Steve Yegge wrote:
I would like this:

  \times 2/3 { c16 c c c c c }

to render with two beamed groups of three notes each, with the two groups connected by a single beam, like so:

c c c  c c c
| | |  | | |
=====  =====
============

I have tuplet numbers and brackets set to transparent.

\relative c' {
    \set tupletSpannerDuration = #(ly:make-moment 1 4)
    \set baseMoment = #(ly:make-moment 1 8)
    \set subdivideBeams = ##t
    \override TupletNumber #'stencil = ##f
    \times 2/3 { \repeat unfold 24 { c16 } } |
}
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