Re: Reheaseals with irregular bars

[Reinhold Kainhofer]

On 2012-10-28 21:35, Jacques Menu wrote:
> Hello folks,
>
> I've been using Lilypond for some time, but Beethoven's Trio X für
> Klavier, Flöte und Fagott causes me much trouble : "\partial" is not
> usable inside a part, and Thema andante con variazioni contains tricky
> rehearsals, like:
>
>
>
> After fighting a lot with the problem, I found:
>
> partialInline = #(define-music-function
> (parser location nom den mus)
> (integer? integer? ly:music?)
> #{
> \set Score.measurePosition = #(ly:make-moment (- $nom) $den)

You don't want (- $nom) here, since that might skip one measure!
In your case you want to set the measure position at the begin of the 
second volta to #(ly:make-moment 0 8), if you want the second volta to 
have the same bar number as the first.

If you want the second volta to have the barnumber of the first volta + 
1, then I would try to set the measure position at the end of the first 
volta to #(ly:make-moment 4 8). I haven't tried it out, but I think that 
should work.


> I always run into messages such as the following (hence my bar numbers
> are wrong) :
>
> Beethoven_WoO37_Fagott_ThemaAndanteConVariazioni.ly:493:16: warning:
> Barcheck failed got 79 expect 81
>
> because I don't know how to specify the correct "size" for the partial
> bars involved (by the way, bar number 64 is already wrong):

I suppose bar 25 is already wrong, right?



> Here is the code I use:
[...]
> \tempoMark #3.0 #"Var. V"
>
> % -------------------------------------------------------------------------
> \repeat volta 2
> % -------------------------------------------------------------------------
> {
>
> \partialInline #1 #8

Here you don't want to set the measure position to #(ly:make-moment (- 
1) 8) of measure 79, since you are already in measure 79. If you set it 
to -1/8, like you do, then this means after the next eighth note measure 
79 will start...

You rather want to set the measure position to 3/8 of bar 79, which 
means that after the eight rest measure 80 will start...


The only reason why \partial sets the measure position to -1/8 is that 
the first full bar is supposed to be measure 1.
In all other cases (i.e. inside some piece), you don't ever want to set 
the measure position to a negative value, as that will skip a measure in 
the measure count.

Cheers,
Reinhold

--
------------------------------------------------------------------
Reinhold Kainhofer, address@hidden, http://www.kainhofer.com
 * Financial & Actuarial Math., Vienna Univ. of Technology, Austria
 * http://www.fam.tuwien.ac.at/, DVR: 0005886
 * Edition Kainhofer, Music Publisher, http://www.edition-kainhofer.com