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Re: tie and slur problem


From: Rutger Hofman
Subject: Re: tie and slur problem
Date: Tue, 28 Oct 2014 20:30:44 +0100
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:31.0) Gecko/20100101 Thunderbird/31.1.2

The following code works for me. It depends on two voices having the same predicate \voiceTwo. Note that you will probably want to tune the shape of the voiceTwo slur, it is wider than in your original.

\new Score {
    \new Staff <<
        \new Voice \relative c' {
            \voiceOne
            g'2.( bes4 |
            a4)
        }
        \new Voice \relative c' {
            \voiceTwo
            c1~ |
            c4
        }
        \new Voice \relative c' {
            \voiceTwo
            e1( |
            f4)
        }
    >>
}

On 10/28/2014 02:33 PM, Urs Liska wrote:

Am 28.10.2014 09:42, schrieb Dr. Bernhard Kleine:
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There should be a tie between the two c and a slur from e to f.  and a slur
from g  over b(bes) to a in the right hand. The upper g and b and a are in a 
separate voice and no problem.
But how to code the tie and the slur in voiceTwo? Between <c e> to < c f>

You can force the slur to be printed upwards through either \slurUp (and
\slurNeutral afterwards) or the direction operator:

<c' e'>2 ^( ~ <c' f'> )


This won't look very good, though, so you will have to tweak the slur
later, presumably with \shape.
But it will give you a semantically correct rendering, and I strongly
suggest to let this untouched as long as possible (i.e. only start
tweaking when you either can't read the output at all or when you have
to produce better final output).


HTH
Urs



Schnipsel from Missa in C from Anton Bruckner

Bernhard


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