Re: baseMoment and beatStructure

[Pierre Perol-Schneider]

Hi Dave,

As Phil already mentioned, it'd be easier if there was a time signature. 3/4 ? 6/8 ? 3/8 ??

As far as I understood your message I'd do:

\version "2.18.2"

{
  \time 6/8
  \set Timing.beatStructure = #'(1 1 1 1 1 1)
  r2.
  \tuplet 3/2 8 { bes,16 ( c d ees f g a bes c d ees e f g a bes f d ) }
  %% or:
  % \tuplet 3/2 { bes,16 ( c d ees f g a bes c d ees e f g a bes f d ) }
}

HTH,

Pierre

2015-03-13 17:21 GMT+01:00 Phil Holmes <address@hidden>:

----- Original Message ----- From: "Dave Higgins" <address@hidden>
To: <address@hidden>
Sent: Friday, March 13, 2015 4:06 PM
Subject: baseMoment and beatStructure

I have been banging my head against the wall with this for the longest time.

What I'm looking for with this is 3 16th notes single beam 3 more 16th
notes single beam and 3 more 16th notes.

What I get is 12 16th notes beamed together.

r2. \tuplet 3/2 8 { \set Timing.baseMoment = #(ly:make-moment 1/8) \set
Timing.beatStructure = #'(3 3 3) bes,16 ( c d ees f g a bes c d ees e f
g a bes f d ) }

I've tried many, many combinations and have never found one that
accomplishes what I'd like.

Maybe I'm using the wrong constructs?

Have another look at the NR:

"If a beamExceptions rule is defined for the time signature in force, that rule alone is used to determine the beam placement; the values of baseMoment and beatStructure are ignored."

The default time signature is 4/4, which does have a beamExceptions rule: as the NR says, you have to clear that rule.

--
Phil Holmes

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