Am 10.11.2016 um 08:53 schrieb Federico Bruni:
Hi
As it's written in the documentation, "If there are more repeats
than there are alternate endings, the earliest repeats are given
the first alternative".
If I want to change this behaviour I should use manual repeats? Or
there's a smarter way?
This is what I'd like to achieve:
\repeat volta 4 {
c1
}
\alternative {
{ d1 } % 1st alternative
{ e1 } % 2nd alternative
{ f1 } % 3rd and 4th alternatives
}
Thanks
Federico
You will find this in the documentation for version 2.18.2 in
chapter 1.4.1 long repeats: Your third and fourth alternative should
be something like
\set Score.repeatCommands = #'((volta "3, 4") end-repeat)
Regards
Bernhard
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