Re: How to prevent ly:stencil-rotate to modify dimensions

[Torsten Hämmerle]

Hi Harm,

David is right - it's the bounding box being rotated. As bounding boxes can
only have heights and widths in vertical and horizontal direction (there
isn't even such a thing as an italic slant in LilyPond), the resulting new
bounding box's height and width increases.

I usually solve this problem by calculating the desired X-extent and
Y-extent and set the stencil dimensions.
In scheme, I use (ly:stencil-outline stencil point-stencil) to rotate
stencil using the dimensions of point-stencil so that the bounding box isn't
distorted .

*Example:* I've created a fake slanted markup command by combining rotate,
scale, rotate back, scale (because there is no shearing) that keeps the
original stencil extent. 
Without stencil extent manipulations (using point-stencil dimensions etc.)
the resulting bounding box would be ridiculously high and totally unusable.

%%%%%%%%%%%

\version "2.19.81"

#(define-markup-command
  (slanted layout props arg)
  (markup?)
  #:category font
  #:properties ((slant-angle 12))
  "Fake a slanted font"
  (let* ((alpha-rad (* 0.5 (acos (tan (* (/ PI -180) slant-angle)))))
          (alpha-deg (* (/ 180 PI) alpha-rad))
          (stencil (if (markup? arg) (interpret-markup layout props arg)
empty-stencil))
          )
    (ly:stencil-outline
      (ly:stencil-scale
       (ly:stencil-rotate
        (ly:stencil-scale
         (ly:stencil-rotate (ly:stencil-outline stencil point-stencil) 45 0
0)
         1 (* (tan alpha-rad)))
        (* (- alpha-deg)) 0 0)
       (* (sqrt 2) (cos alpha-rad)) (/ 0.5 (sqrt 0.5) (sin alpha-rad)))
     stencil)))


\markup \override #'(box-padding . 0) \box \slanted "Poor man’s slanted
Text"

poor-mans-slanted.png
<http://lilypond.1069038.n5.nabble.com/file/t3887/poor-mans-slanted.png>  

This is a simple case just keeping the original extents, but in the end, the
desired new bounding box (i.e. stencil extent) has to be calculated
explicitly depending on the desired output, I couldn't find an automatic
solution either.
Simple trigonometric functions are all you need - it could be worse... ;)

All the best,
Torsten



--
Sent from: http://lilypond.1069038.n5.nabble.com/User-f3.html