Re: [lwip-users] Pbuf_cat and pbuf_free question

[Sergio R. Caprile]

Well, I'm no expert on whatever you are trying to do with this, so take 
it with a grain of salt.

you alloc a pbuf (1)
then you concatenate to the tail of another pbuf (0)
now (1) does not exist anymore as a lonely pbuf but is attached to (0), 
all that exists now is (0).
Somehow, you are supposed to have alloced (0), because it exists, right ?
You then send (0)
You have to free (0), not (1), but (0), unless you plan to use it again, 
but in that case, you won't allocate another "(1)", will you ? No, you 
won't.

If this does not fit your line of thought, perhaps you need to use 
pbuf_chain() or develop another strategy for your application code.