[Octave-bug-tracker] [bug #33218] transpose (') operator not working on scalar structs

[Rik]

Update of bug #33218 (project octave):

                  Status:                    None => Confirmed              

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Follow-up Comment #1:

This bug is confirmed on both 3.4.0 and the development branch.  Very simple
test code to reproduce is


s.a = 1;
s'
error: unary operator `'' not implemented for `scalar struct' operands


For the original reporter, there are several workarounds.  One would be to use
a dummy index variable in the loop like so:


for i = 1:numel (STRUCT_LIST)
  ITEM = STRUCT_LIST(i);
  ...
end


A second approach would to use reshape() to get the row vector you are looking
for rather than the combination of (:) to produce a column vector and
transpose ' to change the column vector to a row vector.  For example:


for ITEM = reshape (STRUCT_LIST, 1, numel (STRUCT_LIST))
  ...
end


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