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[Octave-bug-tracker] [bug #37882] printf('%4d', -0) prints 0
From: |
Rik |
Subject: |
[Octave-bug-tracker] [bug #37882] printf('%4d', -0) prints 0 |
Date: |
Wed, 27 Feb 2013 15:59:11 +0000 |
User-agent: |
Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:19.0) Gecko/20100101 Firefox/19.0 |
Update of bug #37882 (project octave):
Status: None => Need Info
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Follow-up Comment #2:
I think this is actually the expected behavior.
The IEEE floating point standard store numbers in a format with a signbit,
mantissa, and exponent. It is therefore possible to have a mantissa of 0 and
the signbit either set or unset which leads to -/+ 0.
When you call 'printf ("%4d", -0)' you are asking the printf routine to
convert a floating point number to an integer format. The integers are stored
using two's complement format and there is only a single possible zero for the
integers which is +0.
If you agree that this is correct I will close this bug.
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- [Octave-bug-tracker] [bug #37882] printf('%4d', -0) prints 0,
Rik <=