[Octave-bug-tracker] [bug #38577] Eig returns non-unitary transformation matrix

[anonymous]

Follow-up Comment #3, bug #38577 (project octave):

Hi,


> The zero vector for x solves this equation and is orthogonal 
> to the other eigenvectors which are all zeros except for a single
> '1' on the diagonal. Octave appears to place this as the very 
> last eigenvector >every time. You can check this with 
> [...]
> So is this issue merely definitional?

Actually it is not merely definitional.
A * 0 = 0 is true for any matrix. The main point is that the
eigen vectors of a hermitian matrix form a complete basis.
With one zero vector this is not true, one vector is missing.

Actually, I didn't construct this example on purpose, but found it
while debugging a  script, where I perform base transformations into the basis
of eigen vectors of a hermitian matrix. At least
in quantum mechanics this is essential.

Peter

P.S. I'm sorry, but I still have to read the bug-tracker documentation to
understand the mark-up.



    _______________________________________________________

Reply to this item at:

  <http://savannah.gnu.org/bugs/?38577>

_______________________________________________
  Nachricht gesendet von/durch Savannah
  http://savannah.gnu.org/