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From: | Pantxo Diribarne |
Subject: | [Octave-bug-tracker] [bug #44794] image package: imtransform should use 0 instead of NaN for the default extrapolation value |
Date: | Tue, 14 Apr 2015 20:43:21 +0000 |
User-agent: | Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:37.0) Gecko/20100101 Firefox/37.0 |
Follow-up Comment #9, bug #44794 (project octave): @H.G.: because of the way I understood ML doc :-): xdata = [1 3] doesn't mean there will be 3 pixels, it means "the coordinate of the last column in the output space will be 3". In that case the output scale is taken equal to the input scale which in turn is computed (here may be the mistake) using diff(udata)/columns(input_im) I was also surprised and about to ask for a test: what does Matlab return for this test? _______________________________________________________ Reply to this item at: <http://savannah.gnu.org/bugs/?44794> _______________________________________________ Message posté via/par Savannah http://savannah.gnu.org/
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