[Octave-bug-tracker] [bug #50500] Behavior of dir() changed and is different from Matlab now

[Dan Sebald]

Follow-up Comment #4, bug #50500 (project octave):

I'm not as familiar with regexp family commands as I should be, but it does
seem like that regexprep() command is attempting to remove the path, but
apparently not quite correctly.  Here's the expression after the file
separator is printed:

(?:^|^.+[/])([^/.]*.[^/]*)?$

That front () is $1, correct?  The second () is $2?  So why is the regexprep
using $1, rather than $2?


        fn = regexprep (fn, re, '$1')


I would think that the file name is on the right side, i.e., $2, and the
expression should be fashioned so that $1 comes out '' if there is no path.

Also, it seems that spaces in file names act the same, but may want to test
that works.

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