Re: f(end) feature?

[John W. Eaton]

On  1-Jan-2003, John W. Eaton <address@hidden> wrote:

| OK, it was not hard.  Here is the patch.

Oops.  It is not that easy.  My code did this:

  void
  tree_argument_list::append (const element_type& s)
  {
    octave_base_list<tree_expression *>::append (s);

    if (s && s->is_identifier () && s->name () == "__end__")
      list_includes_magic_end = true;
  }

but (obviously, now) it needs to check the possibility that any
expression type might also contain a magic end token.  Should not be
too hard, but will require some new code in all the expression types.
Will try to do tomorrow, and make a new snapshot within a day or two.
In the meantime, if you want "end" to work, you can comment out the if
statement in this function (but leave the assignment of true to
list_includes_magic_end)

jwe