Re: Making bsxfun automatic

[Michael D. Godfrey]

On 8/3/11 8:54 PM, Jordi Gutiérrez Hermoso wrote:
> While bsxfun works, it's obscure, people don't know about it, and
> frankly, it's just damn ugly, and I shouldn't feel proud about myself
> for using it to solve something. People should just attempt the
> multiplication they want with .* and be happy it works. Numpy's
> approach is just that: bsxfun is just simply "automatic" and it seems
> much nicer. We could implement this without breaking any Matlab code,
> making it a nice Octave extension.
>
> Any objections?
>
> - Jordi G. H.
None!  This is definitely a good idea.

Michael