Re: Handling "parfor" as "for"

[Søren Hauberg]

tor, 29 09 2011 kl. 02:58 -0400, skrev John W. Eaton:
> Now Octave can accept statements of the form
> 
>   parfor LHS = EXPR BODY end
>   parfor ( LHS = EXPR, MAXPROC ) BODY end

Does it have the corresponding 'end's ? I.e. can I write

  parfor LHS = EXPR
    BODY
  endfor

or

  parfor LHS = EXPR
    BODY
  endparfor

?

Søren