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| From: | Daniel J Sebald |
| Subject: | Re: Preserving signbit for range operator |
| Date: | Mon, 25 Feb 2013 14:48:07 -0600 |
| User-agent: | Mozilla/5.0 (X11; U; Linux x86_64; en-US; rv:1.9.2.24) Gecko/20111108 Fedora/3.1.16-1.fc14 Thunderbird/3.1.16 |
On 02/25/2013 02:37 PM, Daniel J Sebald wrote:
PS: A bit arbitrary, but this result
Sorry, forgot to erase that bit. I was going to inquire about the result octave:25> [1:0:1] ans = [](1x0)where the increment is zero. Technically, one could argue [a:0:b] = a. That is, there may be an infinite number of integer values K for which a+K*0 < b, but all values of a+K*0 are a. Arbitrary choice I suppose.
Dan
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