Re: @(x) plus(x,++j)

[Ben Abbott]

On May 23, 2014, at 7:43 AM, Muhali <address@hidden> wrote:

> right. I missed the argument for f. So what I meant was
> 
> feval(f, 0)
> 
> and, resp.,
> 
> feval(@(x) plus(x,++j), 0)

I'll use a simpler version of your function.

        j = 0
        f = @() ++j ;

f()
ans =  1
 f()
ans =  2
 f()
ans =  3
 f()
ans =  4

However, in the global space the value of "j" has not changed. 

j
j = 0

"j" is only changing in the variable space local to the function "f"

Each of the statements like below are independent instances of identical 
functions.

        feval(@() ++j, 0)

Meaning that there the initial value for "j" is inherited from the command line 
variable space, but each instance of the function modifies it in its local 
space.

Ben