Re: Help with ismatrix compatibility testing

[Kai Torben Ohlhus]

On Wed, May 28, 2014 at 12:19 AM, Rik <address@hidden> wrote:

5/27/14

Octave has had the ismatrix() command since 2002, but Matlab added one in
2010 and it doesn't appear that the two are exactly the same.

Could someone with a recent edition of Matlab (>2010) run the following and
report the results.

It might be easiest to use "diary on", run the commands, and then "diary
off" and upload the file since there are quite a few tests.

Commands to run:

ismatrix ({1,2;3,4})
[x(1:2,1:2).a] = deal (1,1,1,1);
ismatrix (x)
ismatrix ([])
ismatrix (zeros (10, 0))
ismatrix (zeros (0,10))
x = zeros (0,10,0,0,0)
size (x)
ndims (x)
ismatrix (x)
x = zeros (0,10,0,1,0)
ismatrix (x)
isscalar ({1})
isvector ([])
isvector (1)
isvector (zeros (1,0))
isvector (cell (1,3))

Thanks,
Rik

For MATLAB R2013b the result is:

>> ismatrix ({1,2;3,4})

ans =

     1

>> [x(1:2,1:2).a] = deal (1,1,1,1);

>> ismatrix (x)

ans =

     1

>> ismatrix ([])

ans =

     1

>> ismatrix (zeros (10, 0))

ans =

     1

>> ismatrix (zeros (0,10))

ans =

     1

>> x = zeros (0,10,0,0,0)

x =

   Empty array: 0-by-10-by-0-by-0-by-0

>> size (x)

ans =

     0    10     0     0     0

>> ndims (x)

ans =

     5

>> ismatrix (x)

ans =

     0

>> x = zeros (0,10,0,1,0)

x =

   Empty array: 0-by-10-by-0-by-1-by-0

>> ismatrix (x)

ans =

     0

>> isscalar ({1})

ans =

     1

>> isvector ([])

ans =

     0

>> isvector (1)

ans =

     1

>> isvector (zeros (1,0))

ans =

     1

>> isvector (cell (1,3))

ans =

     1

Best,

Kai