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Re: [Qemu-arm] [PATCH v12 7/9] hw/ptimer: Fix counter - 1 returned by pt


From: Dmitry Osipenko
Subject: Re: [Qemu-arm] [PATCH v12 7/9] hw/ptimer: Fix counter - 1 returned by ptimer_get_count for the active timer
Date: Tue, 8 Mar 2016 22:11:29 +0300
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:38.0) Gecko/20100101 Thunderbird/38.6.0

08.03.2016 06:43, Peter Crosthwaite пишет:
On Tue, Feb 2, 2016 at 7:19 AM, Dmitry Osipenko <address@hidden> wrote:
30.01.2016 19:43, Dmitry Osipenko пишет:

Due to rounding down performed by ptimer_get_count, it returns counter - 1
for
the active timer. That's incorrect because counter should decrement only
after
period been expired, not before. I.e. if running timer has been loaded
with
value X, then timer counter should stay with X until period expired and
decrement after. Fix this by adding 1 to the counter value for the active
and
unexpired timer.

Signed-off-by: Dmitry Osipenko <address@hidden>
---
   hw/core/ptimer.c | 2 +-
   1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/hw/core/ptimer.c b/hw/core/ptimer.c
index 62f8cb1..b2044fb 100644
--- a/hw/core/ptimer.c
+++ b/hw/core/ptimer.c
@@ -136,7 +136,7 @@ uint64_t ptimer_get_count(ptimer_state *s)
                   if ((uint32_t)(period_frac << shift))
                       div += 1;
               }
-            counter = rem / div;
+            counter = rem / div + (expired ? 0 : 1);

               if (expired && counter != 0) {
                   /* Wrap around periodic counter.  */


Noticed one nit here:

There is possibility to return timer counter = limit + 1, if the following
ptimer calls execute in less than 1ns.

         ptimer_run(t, 1);
         // counter = 91, if set() count executed in less than 1ns
         ptimer_set_count(t, 90);
         counter = ptimer_get_count(t);

Likely, it would be impossible to trigger that issue on a real current
machine.
But the fix is trivial, I'll incorporate it in V13 if it looks fine:

---
@@ -76,20 +76,20 @@ static void ptimer_tick(void *opaque)
  {
      ptimer_state *s = (ptimer_state *)opaque;
      s->delta = 0;
      ptimer_reload(s);
  }

  uint64_t ptimer_get_count(ptimer_state *s)
  {
+    int64_t now = qemu_clock_get_ns(QEMU_CLOCK_VIRTUAL);
      uint64_t counter;

-    if (s->enabled && s->delta != 0) {
-        int64_t now = qemu_clock_get_ns(QEMU_CLOCK_VIRTUAL);
+    if (s->enabled && s->delta != 0 && now != s->last_event) {
          int64_t next = s->next_event;
          bool expired = (now - next >= 0);
          bool oneshot = (s->enabled == 2);

          /* Figure out the current counter value.  */
          if (expired && (oneshot || use_icount)) {
              /* Prevent timer underflowing if it should already have
                 triggered.  */
@@ -131,17 +131,17 @@ uint64_t ptimer_get_count(ptimer_state *s)
              } else {
                  if (shift != 0)
                      div |= (period_frac >> (32 - shift));
                  /* Look at remaining bits of period_frac and round div up
if
                     necessary.  */
                  if ((uint32_t)(period_frac << shift))
                      div += 1;
              }
-            counter = rem / div;
+            counter = rem / div + (expired ? 0 : 1);


Sorry about the long delays. Im wondering what this has to do with
expiration though? the commit message suggests you want to change the
rounding scheme, so can that be done directly with DIV_ROUND_UP?

Regards,
Peter

              if (expired && counter != 0) {
                  /* Wrap around periodic counter.  */
                  counter = s->limit - (counter - 1) % s->limit;
              }
          }
      } else {
          counter = s->delta;


--
Dmitry

Hi Peter,

The expiration check is needed because timer should stay with 0 for a one period before doing wrap around. Using DIV_ROUND_UP directly, timer would wrap around immediately once now > next (i.e. after 1 ns) regardless of the period value, and DIV_ROUND_UP can't be used because it would cause integer overflow of (n) + (d) due to the left shifting of the "rem" and "div".

#define DIV_ROUND_UP(n,d) (((n) + (d) - 1) / (d))


No worries, I can wait as much as needed :)

--
Dmitry



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