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[Qemu-devel] FreeBSD-amd64 guest, monitor does not respond


From: Juergen Lock
Subject: [Qemu-devel] FreeBSD-amd64 guest, monitor does not respond
Date: Sun, 16 Jan 2005 23:39:44 +0100

I was curious today and tried the FreeBSD-amd64 install iso in qemu,
        qemu-system-x86_64 -m 256 -monitor stdio -cdrom 
5.3-RELEASE-amd64-bootonly.iso -boot d
and, (actually i tried miniinst first, but bootonly is smaller and shows
the same result) qemu hangs when starting the kernel, the monitor does not
respond, all I can do is ^c it.  (the started kernel is supposed to print
messages starting with the copyright but it doesnt even get to that.)

 So, question: what does it mean when the monitor doesnt respond?
infinite loop in the translated code?

 Well, i just tried it in gdb and this is what i get when ^c'ing it:

Program received signal SIGINT, Interrupt.
[Switching to Thread 1077076096 (LWP 18901)]
0x080f00ee in do_interrupt64 (intno=13, is_int=0, error_code=0, 
    next_eip=4626569007820963840, is_hw=0) at softmmu_header.h:237
237     {
(gdb) bt
#0  0x080f00ee in do_interrupt64 (intno=13, is_int=0, error_code=0, 
    next_eip=4626569007820963840, is_hw=0) at softmmu_header.h:237
#1  0x080a85ae in cpu_x86_exec (env1=0x908b528)
    at /home/knoppix/qemu/qemu/cpu-exec.c:199
#2  0x0804e5f1 in main_loop () at /home/knoppix/qemu/qemu/vl.c:2675
#3  0x0804f5cc in main (argc=161702, argv=0x0)
    at /home/knoppix/qemu/qemu/vl.c:3671
(gdb) 

 so its processing interrupts apparently, but why does that `hang' qemu?

 mirrors for bootonly and the other isos can be found here:
        http://mirrorlist.freebsd.org/
for example:
        ftp://ftp.fr.freebsd.org/pub/FreeBSD/releases/amd64/ISO-IMAGES/5.3/
(bootonly is some 20M, the others are larger)

 Cheers,
        Juergen




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