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[Qemu-devel] Bug: FC6 x86_64 guest causes illegal instructions on QEMU 0
From: |
Kevin Kofler |
Subject: |
[Qemu-devel] Bug: FC6 x86_64 guest causes illegal instructions on QEMU 0.8.2 on 32-bit P4 host |
Date: |
Fri, 27 Oct 2006 23:18:54 +0000 (UTC) |
User-agent: |
Loom/3.14 (http://gmane.org/) |
I have encountered an issue which I think is a bug in QEMU. I'm running QEMU
0.8.2 (from the Fedora Extras RPM: qemu-0.8.2-3.fc6.i386.rpm) on a 32-bit
Pentium IV running Fedora Core 6 (as host OS). (And yes, that RPM is built with
compat-gcc-32 (GCC 3.2), not GCC 4.x, so that's not the problem.) Using
qemu-system-x86_64, I can install (using the x86_64 boot.iso and a HTTP
installation) and run CentOS 4.4 x86_64 (as the guest) with no problems. (Even
the speed is acceptable when keeping in mind that this is an emulated
instruction set.)
Unfortunately, trying to do the same thing with Fedora Core 6 as the guest
doesn't work:
* If I try to boot the FC6 x86_64 boot.iso, it only goes as far as "Booting
kernel." and then the emulated machine locks up. Trying to boot the vmlinuz
directly (bypassing the syslinux bootloader) doesn't change anything. Looking
at the debugging logs, I see the installer hits an "illegal" instruction (an
instruction unknown to QEMU actually, as the boot.iso is known to work on real
x86_64 hardware) early in the kernel.
* So what I tried next is setting up an FC6 x86_64 chroot in the installed
CentOS 4.4 x86_64 guest using the "mock" tool. This works as long as it is only
setting up the chroot from the host system, but as soon as a binary from the
FC6 chroot is run, it hits an illegal instruction again. (This time it just
kills the FC6 executable and returns to CentOS 4.4 bash with the error.) So
it's not just the kernel which doesn't work.
Is this enough information to reproduce and fix the problem? (The images I used
are all publically available.) Or do you want me to provide some logs? (Which
ones?)
Kevin Kofler
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