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[Qemu-devel] [bug #18161] FC6 x86_64 guest doesn't work in QEMU 0.8.2 on


From: Kevin Kofler
Subject: [Qemu-devel] [bug #18161] FC6 x86_64 guest doesn't work in QEMU 0.8.2 on 32-bit P4 host
Date: Tue, 31 Oct 2006 02:51:57 +0000
User-agent: Mozilla/5.0 (compatible; Konqueror/3.5; Linux) KHTML/3.5.4 (like Gecko)

URL:
  <http://savannah.nongnu.org/bugs/?18161>

                 Summary: FC6 x86_64 guest doesn't work in QEMU 0.8.2 on
32-bit P4 host
                 Project: qemu
            Submitted by: kevinkofler
            Submitted on: Dienstag 31.10.2006 um 02:51
                Category: None
                Severity: 3 - Normal
              Item Group: None
                  Status: None
                 Privacy: Public
             Assigned to: None
             Open/Closed: Open

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Details:

(NOTE: I tried sending directly to the mailing list, but there's no way I can
get the message through that way, so let's try this way.)

I have encountered an issue which I think is a bug in QEMU. I'm running QEMU
0.8.2 (from the Fedora Extras RPM: qemu-0.8.2-3.fc6.i386.rpm) on a 32-bit
Pentium IV running Fedora Core 6 (as host OS). (And yes, that RPM is built
with compat-gcc-32 (GCC 3.2), not GCC 4.x, so that's not the problem.) Using
qemu-system-x86_64, I can install (using the x86_64 boot.iso and a HTTP
installation) and run CentOS 4.4 x86_64 (as the guest) with no problems.
(Even the speed is acceptable when keeping in mind that this is an emulated
instruction set.)

Unfortunately, trying to do the same thing with Fedora Core 6 as the guest
doesn't work:
* If I try to boot the FC6 x86_64 boot.iso, it only goes as far as "Booting
kernel." and then the emulated machine locks up. Trying to boot the vmlinuz
directly (bypassing the syslinux bootloader) doesn't change anything. Looking
at the debugging logs, I see the installer hits an "illegal" instruction (an
instruction unknown to QEMU actually, as the boot.iso is known to work on
real x86_64 hardware) early in the kernel.
* So what I tried next is setting up an FC6 x86_64 chroot in the installed
CentOS 4.4 x86_64 guest using the "mock" tool. This works as long as it is
only setting up the chroot from the host system, but as soon as a binary from
the FC6 chroot is run, it hits an illegal instruction again. (This time it
just kills the FC6 executable and returns to CentOS 4.4 bash with the error.)
So it's not just the kernel which doesn't work.

Is this enough information to reproduce and fix the problem? (The images I
used are all publically available.) Or do you want me to provide some logs?



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