[Qemu-devel] [help] When T0 is updated to last exectued TB

[Wang,zhi]

Hi, 
I am a newcomer to QEMU. I am trying to understand the QEMU code. I am a little 
bit confused about the following code about chaining TBs with direct jump 
(cpu-exec.c, line 611, I edited it to remove #ifdef to make it clear to 
discussion): 
                if (T0 != 0 && tb->page_addr[1] == -1 ) {
                    spin_lock(&tb_lock);
                    tb_add_jump((TranslationBlock *)(long)(T0 & ~3), T0 & 3, 
tb);
                    spin_unlock(&tb_lock);
                }

Say, if I am compile an i386-softmmu target on i386 host, T0 is %ebx. From the 
code, T0 should contain the point to the last executed translation block. I 
checked many code but couldn't find where T0 is updated to the last executed 
block. Is there anyone willing to give me a hint? Thanks


Pangy



       
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