[Qemu-devel] [Bug 424458] Re: PCI read data register offset

[Alex Williamson]

I think the problem is that you're trying to do a 4-byte read that goes
off the end of PCI_DATA.  Try doing an inpw() to read the last word.
Simple test program shows it works properly for me.

** Changed in: qemu
       Status: New => Invalid

-- 
PCI read data register offset
https://bugs.launchpad.net/bugs/424458
You received this bug notification because you are a member of qemu-
devel-ml, which is subscribed to QEMU.

Status in QEMU: Invalid

Bug description:
I may have found a bug with the PCI code.

If I execute the following code as a quest, 

  #define  PCI_ADDR     0x0CF8
  #define  PCI_DATA     0x0CFC

  // bus 0, dev 0, func 0, addr 0
  outpd(PCI_ADDR, 0x80000000);
  
  // read in the dword at addr 0 offset 0
  //  and
  // read in the  word at addr 0 offset 2
  //     and the  word at addr 1 offset 0
  printf("0x%08X  0x%08X", inpd(PCI_DATA), inpd(PCI_DATA+2));


Qemu (0.10.6  Windows build) returns

    0x12378086  0xFFFFFFFF

It seems that if I read from any offset other than PCI_DATA, QEMU is returning 
0xFFFFFFFF.

Shouldn't PCI_DATA+1, PCI_DATA+2, and PCI_DATA+3 all be registered to the PCI 
emulation?

Again, this is the Windows build at
  http://homepage3.nifty.com/takeda-toshiya/qemu/index.html
so it is unknown if it is the main CVS.  I didn't check, though I can't image 
this error lasting this long.  I would image someone would have noticed it 
already.  So it might be assosiated with the Windows build only.  Thanks.