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From: | Denis V. Lunev |
Subject: | Re: [Qemu-devel] [PATCH 1/4] fifolock: create rfifolock_is_locked helper |
Date: | Mon, 2 Nov 2015 16:39:49 +0300 |
User-agent: | Mozilla/5.0 (X11; Linux x86_64; rv:38.0) Gecko/20100101 Thunderbird/38.3.0 |
On 11/02/2015 04:12 PM, Stefan Hajnoczi wrote:
On Sun, Nov 01, 2015 at 04:55:51PM +0300, Denis V. Lunev wrote:On 10/30/2015 06:41 PM, Stefan Hajnoczi wrote:On Wed, Oct 28, 2015 at 06:01:02PM +0300, Denis V. Lunev wrote:+int rfifolock_is_locked(RFifoLock *r);Please use bool instead of int.diff --git a/util/rfifolock.c b/util/rfifolock.c index afbf748..8ac58cb 100644 --- a/util/rfifolock.c +++ b/util/rfifolock.c @@ -48,7 +48,7 @@ void rfifolock_lock(RFifoLock *r) /* Take a ticket */ unsigned int ticket = r->tail++; - if (r->nesting > 0 && qemu_thread_is_self(&r->owner_thread)) { + if (r->nesting > 0 && rfifolock_is_locked(r)) { r->tail--; /* put ticket back, we're nesting */ } else { while (ticket != r->head) { @@ -69,10 +69,15 @@ void rfifolock_unlock(RFifoLock *r) { qemu_mutex_lock(&r->lock); assert(r->nesting > 0); - assert(qemu_thread_is_self(&r->owner_thread)); + assert(rfifolock_is_locked(r)); if (--r->nesting == 0) { r->head++; qemu_cond_broadcast(&r->cond); } qemu_mutex_unlock(&r->lock); } + +int rfifolock_is_locked(RFifoLock *r) +{ + return qemu_thread_is_self(&r->owner_thread); +}The function name confused me since "does the current thread hold the lock?" != "does anyone currently hold the lock?". I suggest: bool rfifolock_held_by_current_thread(RFifoLock *r) { return r->nesting > 0 && qemu_thread_is_self(&r->owner_thread); } Then the r->nesting > 0 testing can also be dropped by callers, which is good since rfifolock_is_locked() does not return a meaningful result when r->nesting == 0.actually the function is broken in the current state: aio_context_acquire() aio_context_release() aio_context_is_locked() will return true. the problem is that owner thread is not reset on lock release.The owner thread field is only valid when nesting > 0.with your proposal the function become racy if called from outer thread. I need to think a bit here.This is thread-safe: bool owner; qemu_mutex_lock(&r->lock); owner = r->nesting > 0 && qemu_thread_is_self(&r->owner_thread); qemu_mutex_unlock(&r->lock); return owner;
yep, I know. But I do not want to take the lock for check. IMHO it would be better to @@ -68,11 +68,16 @@ void rfifolock_lock(RFifoLock *r) void rfifolock_unlock(RFifoLock *r) { qemu_mutex_lock(&r->lock); - assert(r->nesting > 0); - assert(qemu_thread_is_self(&r->owner_thread)); + assert(rfifolock_is_owner(r)); if (--r->nesting == 0) { + qemu_thread_clear(&r->owner_thread); r->head++; qemu_cond_broadcast(&r->cond); } qemu_mutex_unlock(&r->lock); } + +bool rfifolock_is_owner(RFifoLock *r) +{ + return r->nesting > 0 && qemu_thread_is_self(&r->owner_thread); +} which does not require lock and thread safe. Den
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