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Re: [Qemu-devel] [PATCH 0/7] int128: reparing broken 128 bit memory calc


From: Pierre Morel
Subject: Re: [Qemu-devel] [PATCH 0/7] int128: reparing broken 128 bit memory calculations
Date: Tue, 10 Nov 2015 13:12:56 +0100
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:38.0) Gecko/20100101 Thunderbird/38.3.0



On 11/10/2015 10:08 AM, Pierre Morel wrote:


On 11/09/2015 01:20 PM, Paolo Bonzini wrote:

On 09/11/2015 13:01, Pierre Morel wrote:
This leads to have UINT64_MAX represented with {1, 0} instead of
{0, UINT64_MAX} while {1, 0} is 2^64. This again leads to have
unnecessary and obfuscating transformations with int128_2_64() to
test for UINT64_MAX and return {1,0} in memory_region_init()
while using inverse translation test{1,0} and return UINT64_MAX
in memory_region_size()>>
Yes, the use of UINT64_MAX for 2^64 is a hack, but it is unrelated to
the signedness of Int128.
OK, we agree it is a hack,
but sorry, I should have missed something,
because I do not understand what this hack is useful for.
It's used in the size argument of memory_region_init*, so that it can
remain an uint64_t.  The size is usually small (up to 2^40, say) unless
it is 2^64 meaning "the whole address space".  The latter case is
covered by UINT64_MAX.

Paolo


OK, I understand, thanks for having taking time for me.

To sum-up size is a size :-) and not an offset in memory.

Size of UINT64_MAX does not exist but we can live without it, having
a description for "whole address space", 2^64, can be useful.

Even there may be other solutions like taking 0 for 2^64,
if a memory size of 0 has no meaning,
but it could be misleading too.

So I do not see better solution for this interesting problematic.




My problem with this came because usually, on hardware, region are easier
described by start/end rather than by start/size.
But  changing this in the actual implementation would be too much.





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