[Qemu-devel] qemu 2.10.2 : util/qemu-thread-posix.c: 64: qemu_mutex_lock: Assertion 'mutex->initialized' failed

[Eva Chen]

Hello,

I am working on compiling QEMU 2.10.2 to a static library.

Everything works fine in compiling QEMU to an execution
file(qemu-system-aarch64), but after I link all .o and .a file to create a
QEMU library and write a c file to call qemu_main() in qemu/util/vl.c(I
have changed the name "main()" into "qemu_main()"), then it shows this
error message.

util/qemu-thread-posix.c: 64: qemu_mutex_lock: Assertion
'mutex->initialized' failed.
Abort (core dumped)


The information of gdb's backtrace is shown as bellow
(gdb) bt

*#o Ox00007ffff05b31f7 in raise () at /usr/lib64/libc.so.6 #1
0x00007ffff05b48e8 in abort () at /usr/lib64/libc.s0.6 #2
0x00007ffff05ac266 in assert fail base () at /usr/lib64/libc.so.6 #3
0x00007ffff05ac312 in 0 at /usr/lib64/libc.so.6 #4 0x00000000005c47e3 in
qemu_mutex_lock (address@hidden <rcu_registry lock>) at
util/qemu -thread-posix.c:64 #5 0x00000000005d5b46 in rcu_register_thread
() at util/rcu.c:290, #6 0x00007ffff5a790de in rcu_init_complete () at
util/rcu.c:318, #7 Ox00007ffff7dea503 in _dl_init_internal () at
/lib64/ld.linux-x86-64.50.2 #8 0x00007ffff7ddclaa in _dl_start_user () at
/lib64/ld.linux - x86-64.so.2, #9 0x0000000000000014 in ()*

I found out that it aborted before conducted to the main function in QEMU
Also,  I use si and n in gdb to see what happened in this QEMU library
it showed  that the address and content of *rcu_registry_lock* would change
when it executed qemu_thread_create() in util/rcu.c:315

$ qemu_thread_create(&thread, "cal_rcu", call_rcu_thread, NULL,
QEMU_THREAD_DETACHED)

This change caused the failure of assert(mutex->initialized) in
qemu_mutex_lock (which called by rcu_register_thread() in call_rcu_thread())


The method that compiling the execution file into a library success on QEMU
2.2.1, but failed on QEMU 2.10.2
Will this error message related to the rcu? Or is there anything suggestion
to solve this error?


I will be grateful for any help.


Eva


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