Re: [Qexo-general] Function return value

[Per Bothner]

Jun Yu wrote:

> My XQuery program "test.xql" is like this:
>
> define function authenticate($username,$password) as boolean {
> let $s:=document("session.xml")/login
> return
>   if ($s/username=$username and $s/password=$password) then
>      true
>   else
>      false
> }

'true' and 'false' are parsed as node tests, i.e. as short for
./child::true and ./child::false.  Qexo is warning you that context
(i.e. the current node '.') isn't defined here.

You probably meant to write:

  return
    if ($s/username=$username and $s/password=$password) then
      true()
    else
      false()

or just plain:

  return
    $s/username=$username and $s/password=$password

Likewise:

  if (authenticate(...) = true) then ...

should be:

  if (authenticate(...) = true()) then ...

or better:
   if (authenticate(...)) then ...
--
        --Per Bothner
address@hidden   http://per.bothner.com/