Re: removing elements while looping with an index, and return values from Set add

[Ken Gosier]

--- Paul Johnson <address@hidden> wrote:
> Well, maybe I can.  Am I right in guessing that your
> pseudo code like so:
>       if (  condition[i]  )
> is in the actual program something more elaborate, like
> 
>        if (condition[i]== [thisElem getValue])
> 


It is pretty much like this, except that the conditions are
not mutually exclusive. That is, in oldList, you have 3
types of elements:
- Those that satisfy condition[0]
- Those that satisfy condition[1]
- Those that satisfy neither.

Basically, the problem is that the elements that satisfy
condition[0] will get removed. Then when I'm looping to
find those that satisfy condition[1], the index falls off
the end of the List.


=====
Ken Gosier
address@hidden

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