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[Bug-apl] Defined operator won't accept right constant function
From: |
David B. Lamkins |
Subject: |
[Bug-apl] Defined operator won't accept right constant function |
Date: |
Sat, 05 Jul 2014 15:39:29 -0700 |
The last time I worked on my component-file code was circa SVN 220. At
the time, I was using a defined operator that took a constant function
as its right function. Something akin to this, where g would always be a
constant function, e.g. {1}:
∇z←l (f foo g) r
z←(r f l) (l g r)
∇
At the time, I could call this operator as:
1 {⍺ ⍵} foo {3} 2
2 1 1 3 2
(The above isn't exactly what I was doing... I was using the constant
value by itself. That used to work. This is just illustrative of what I
think that call ought to do, but doesn't in the current build.)
Interestingly, I can still use a constant function on the left of the
operator:
1 {3} foo {⍺ ⍵} 2
2 3 1 1 2
When I try to put a constant function to the right of the operator, this
is what happens:
1 {⍺ ⍵} foo {3} 2
VALUE ERROR
1 λ2 foo λ1 2
^
Are my expectations out of line, or is this a bug?
- [Bug-apl] Defined operator won't accept right constant function,
David B. Lamkins <=
- Re: [Bug-apl] Defined operator won't accept right constant function, Juergen Sauermann, 2014/07/06
- Re: [Bug-apl] Defined operator won't accept right constant function, David Lamkins, 2014/07/08
- Re: [Bug-apl] Defined operator won't accept right constant function, Elias Mårtenson, 2014/07/08
- Re: [Bug-apl] Defined operator won't accept right constant function, David B. Lamkins, 2014/07/08
- Re: [Bug-apl] Defined operator won't accept right constant function, Elias Mårtenson, 2014/07/09
- Re: [Bug-apl] Defined operator won't accept right constant function, David B. Lamkins, 2014/07/09
- Re: [Bug-apl] Defined operator won't accept right constant function, Elias Mårtenson, 2014/07/08
- Re: [Bug-apl] Defined operator won't accept right constant function, David B. Lamkins, 2014/07/08
- Re: [Bug-apl] Defined operator won't accept right constant function, Elias Mårtenson, 2014/07/08