Re: [Bug-apl] Problem with modulo arithmetic on Gaussian integers redux

[Jay Foad]

It got broken in r939. The problem is in Cell.icc:

//-----------------------------------------------------------------------------

inline bool

Cell::integral_within(APL_Complex A, APL_Float B)

{

const APL_Complex C = -A;

   return tolerant_floor(C, B) == tolerant_floor(A, B);

}

//-----------------------------------------------------------------------------

You're missing a minus sign before the second "tolerant_floor".

Jay.

On 14 June 2017 at 13:04, Juergen Sauermann <address@hidden> wrote:

Hi Fred,

not sure what to do about that. On my machine I am getting:

      1J3 ∣ 8J4
0

and your TGI0.apl program seems not to output anything.

Best Regqrds,
Jürgen Sauermann

On 06/14/2017 05:52 AM, Frederick Pitts wrote:

Juergen,

	I'm seeing errors with the mod (∣) operator applied to Gaussian
integers again.  With svn 896, the mod operator yields a nonzero
residual result while the division operator yields an exact Gaussian
integer quotient result as follows

      1J3 ∣ 8J4
1J3
      8J4 ÷ 1J3
2J¯2
      1J3 × 2J¯2
8J4

	I'm running Fedora 25, 64 bit, on an Intel Core i7-6700 4 core
CPU with 16 Gbyte memory.

	The attached TGI0.apl generates many more failure examples if
needed.

Regards,

Fred