Re: exercise 2019/02

[Kacper Gutowski]

On Tue, Apr 14, 2020 at 05:40:26PM +0200, Otto Diesenbacher-Reinmüller wrote:
> 2 making the grade
(...)
> Any hint?

I think all those ranges are mostly a distraction, because it's nowhere 
said you need to handle out-of-range arguments in any graceful way.
I would start with ⍵>table[;2] which is a binary vector for scalar ⍵, 
and then go from that.

My solution would be {table[⎕IO++/⍵∘.>table[;2];3]}.
Few years ago I would try to use ¨ too (I'm still relatively new to APL 
myself), but it kinda feels like writing C in APL and outer product is 
really more natural here when you think about it.

Alternatively you could use dyadic ⍳ to find the first 0 in said vector, 
which then leads to something like {table[(⍵∘.>table[;2])⍳⍤1⊢0;3]}.

-k