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`()' subshell parsing fails in `case' clause
From: |
hcz |
Subject: |
`()' subshell parsing fails in `case' clause |
Date: |
Tue, 03 Jan 2006 13:43:48 +0100 |
Configuration Information [Automatically generated, do not change]:
Machine: i486
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i486'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu'
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL
-DHAVE_CONFIG_H -I. -I../bash -I../bash/include -I../bash/lib -g -O2
uname output: Linux tazzelwurm 2.6.14hcz1d #6 PREEMPT Thu Dec 8 11:56:38 CET
2005 i686 GNU/Linux
Machine Type: i486-pc-linux-gnu
Bash Version: 3.1
Patch Level: 0
Release Status: release
Description:
The closing bracket in a case clause within a () subshell
gets interpreted as the subshell's closing bracket.
Repeat-By:
#!/bin/bash
x=$(
case $(ls) in
example) failsHere;;
esac
)
results in:
/bashbug.sh: line 4: syntax error near unexpected token `;;'
./bashbug.sh: line 4: ` example) failsHere;;'
Fix:
move the offending code out into a function and call the
function from the subshell.
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