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Re: Bug? Explanation??
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From: |
Peter & Kelly Passchier |
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Subject: |
Re: Bug? Explanation?? |
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Date: |
Sat, 31 Dec 2016 11:20:07 +0700 |
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User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:45.0) Gecko/20100101 Thunderbird/45.5.1 |
Thanks Dennis and Grisha! I understand.
I had thought that every line that is piped into bash is it's own shell
alignment, but I understand it's more like sourcing, so these would be
more or less equivalent, right?
r=23; echo $r; echo -e 'r=bc\necho $r' >r; source r
r=23; echo $r; echo -e 'r=bc\necho $r' |bash
Thanks again,
Peter
On 31/12/2559 11:07, Grisha Levit wrote:
> On Fri, Dec 30, 2016 at 11:03 PM, PePa <peterkelly@passchier.net
> <mailto:peterkelly@passchier.net>> wrote:
>
> r=23; echo $r; echo -e "r=bc\necho $r" |bash
>
> You need to escape the |$| in the second echo statement so that |$r| is
> not evaluated to |23| before being echoed.
>
>