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Re: bash 4.4.19
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From: |
Greg Wooledge |
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Subject: |
Re: bash 4.4.19 |
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Date: |
Wed, 19 Sep 2018 08:50:23 -0400 |
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User-agent: |
NeoMutt/20170113 (1.7.2) |
On Wed, Sep 19, 2018 at 08:38:59AM +0300, Евгений Мёдов wrote:
> for i in {1..5}; do
> A A var${i}=$RANDOM
> done
What you want is an array. See <https://mywiki.wooledge.org/BashFAQ/005>.
for i in 1 2 3 4 5; do
var[i]=$RANDOM
done
echo "${var[1]}"
declare -p var
- bash 4.4.19, Евгений Мёдов, 2018/09/19
- Re: bash 4.4.19,
Greg Wooledge <=