Re: Local variable can not unset within shell functions

[alex xmb sw ratchev]

On Thu, Jul 11, 2024, 16:34 alex xmb sw ratchev <fxmbsw7@gmail.com> wrote:

>
>
> On Thu, Jul 11, 2024, 15:42 Dr. Werner Fink <werner@suse.de> wrote:
>
>> Hi,
>>
>> I've a report that with later bash the following which works in bash-4.2
>>
>>  x () {
>>   local x=y
>>   declare -p x
>>   echo $x
>>   unset x
>>   declare -p x
>>   echo $x
>>  }
>>
>> with
>>
>>  linux-40cm:~ # x () {
>>  >   local x=y
>>  >   declare -p x
>>  >   echo $x
>>  >   unset x
>>  >   declare -p x
>>  >   echo $x
>>  >  }
>>  linux-40cm:~ # x
>>  declare -- x="y"
>>  y
>>  -bash: declare: x: not found
>>
>> but with bash-5.X the reporter sees (and complains)
>>
>>  sl15sp5:~ # x () {
>>  >   local x=y
>>  >   declare -p x
>>  >   echo $x
>>  >   unset x
>>  >   declare -p x
>>  >   echo $x
>>  >  }
>>  sl15sp5:~ # x
>>  declare -- x="y"
>>  y
>>  declare -- x
>>
>
> id aay the v5 is more valid as error got replaced by working code (
> var=foo ; sav=$( declare -p var ) ; .. ; eval "$var" ( or maybe another
> noeval version )
>

sorry , eval "$sav" , not $var

greets
>
> ... for global variables it works as expected.
>>
>> Werner
>>
>> --
>>   "Having a smoking section in a restaurant is like having
>>           a peeing section in a swimming pool." -- Edward Burr
>>
>