Re: "printf %d ''" should diagnose the empty string

[#!microsuxx]

the printf %d gets to be no print_out at all
u specify a %<code> but no arg
means it wont try printf at all smth

printf %d '' we can talk about
returns 0
and looks normal so to me

On Tue, Nov 19, 2024, 8:46 PM Paul Eggert <eggert@cs.ucla.edu> wrote:

> Configuration Information [Automatically generated, do not change]:
> Machine: x86_64
> OS: linux-gnu
> Compiler: gcc -std=gnu23
> Compilation CFLAGS: -g -O2
> uname output: Linux penguin.cs.ucla.edu 6.11.6-200.fc40.x86_64 #1 SMP
> PREEMPT_DYNAMIC Fri Nov  1 16:09:34 UTC 2024 x86_64 GNU/Linux
> Machine Type: x86_64-pc-linux-gnu
>
> Bash Version: 5.3
> Patch Level: 0
> Release Status: beta
>
> Description:
>
> printf doesn't diagnose attempts to print empty strings as numbers. This
> doesn't conform to POSIX and disagrees with the traditional Unix printf
> command.
>
> Repeat-By:
>
> printf %d ''
>
> This should behave like "printf %d ' '", and should output a diagnostic
> and exit with status 1; instead it silently exits with status 0.
>
> Fix:
> Attached.