Re: Logical expression works does not work as expected

[Greg Wooledge]

On Sat, Dec 28, 2024 at 15:23:41 -0500, Lawrence Velázquez wrote:
> On Fri, Dec 27, 2024, at 6:47 PM, Greg Wooledge wrote:
> > You might have been raised on some other language where the && and ||
> > operators have different precedence.  In the shell language, they have
> > the same precedence.
> 
> However, the && and || arithmetic operators do have C-like precedence.
> 
>       $ echo "$((1 && 1 || 0 && 0))"
>       1
>       $ echo "$(( ((1 && 1) || 0) && 0 ))"
>       0
> 
> So be aware of context.

Yes.  Safety and consistency are profane words in shell designs.

Every feature is designed independently of every other feature, and
the goal is to trip you up as many times as possible.