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RE: Getting inode counts from "du --inodes" clarification
From: |
SCOTT FIELDS |
Subject: |
RE: Getting inode counts from "du --inodes" clarification |
Date: |
Mon, 13 Feb 2023 20:31:36 +0000 |
No, because I'm looking to get all directories under the given path
represented, as my example shows.
I do want the entire directory tree traversed, but I'm wanting only the number
of top level objects in each directory reported as far as counts are for each
directory.
I appreciate your response.
-----Original Message-----
From: Bernhard Voelker <mail@bernhard-voelker.de>
Sent: Monday, February 13, 2023 1:59 PM
To: SCOTT FIELDS <Scott.Fields@kyndryl.com>
Cc: coreutils@gnu.org
Subject: [EXTERNAL] Re: Getting inode counts from "du --inodes" clarification
On 2/10/23 23:47, SCOTT FIELDS wrote:
> I'm looking to get the number of files in each directory under a given path
> > But only the top level of each directory (don't include files/directories
> from > subdirectories in each processed directory) > > Example from your
> statement:
>
> # du --inodes -d 0 --all /usr
> 119613 /usr
>
> In this case, the number of entries directly within /usr is 15 (files,
> directories, etc), but this is reporting all the files that exists within
> /usr and all other subdirectories.
>
> A script that does what I mean is fairly simple but hardly a simple one
> liner.
>
> --
>
> for directory in $(find <directory> -type d); do echo "$(ls -a $directory \
> | sed '/^\.$/d;/^\.\.$/d'| wc -l) $directory"; done
I see. du(1) traverses the whole directory hierarchy, so that's not wanted
anyway.
And --max-depth only changes which levels get printed and which not).
One could of course try to work with an --exclude pattern, but that's awkward.
Your direction with find(1) looks better - but with the -mindepth and -maxdepth
option:
find /usr -mindepth 1 -maxdepth 1 -printf x | wc -c
12
Does this come closer to what you want to achieve?
Have a nice day,
Berny