Re: [O] execute sbe macro fails

[Eric Schulte]

Hi Torsten,

There are numerous syntactic issues in your example, try the attached
version which works.  Additionally, I've pushed up a change which makes
the sbe macro somewhat more robust so that the quotes around 50 could
now be removed.

| Name  |     ID | 1.1    | 1.2 | 1.3 | 1.4 | 2.1 | 2.2 | 2.3 | 2.4 | 2.5 | 
Extra |   |   |
| Sum   |   Mark |        |     |     |     |     |     |     |     |     |     
  |   |   |
|-------+--------+--------+-----+-----+-----+-----+-----+-----+-----+-----+-------+---+---|
| Name1 | 111111 | 10     |  10 |  10 |  12 |  12 |   3 |   4 |  12 |   3 |     
  | 1 | 5 |
| 2     |     78 | #ERROR |     |     |     |     |     |     |     |     |     
  | 2 | 5 |
| Name2 |  22222 |        |     |     |     |     |     |     |     |     |     
  | 3 | 5 |
|       |      0 | #ERROR |     |     |     |     |     |     |     |     |     
  | 4 | 5 |
| Name3 |  33333 |        |     |     |     |     |     |     |     |     |     
  | 5 | 5 |
|       |      0 | #ERROR |     |     |     |     |     |     |     |     |     
  | 6 | 5 |
#+TBLFM: $14='(sbe score2mark (score $13) (passscore "50"))

#+name: score2mark
#+begin_src python :var score=0 :var passscore=0
def score2mark(score, passscore):
    marklist = [5, 4.3, 4, 3.7, 3.3, 3, 2.7 ,2.3, 2, 1.7, 1.3, 1]
    step=(100-passscore)/(len(marklist)-1)
    if  score < passscore:
           return marklist[0]
    for mark in marklist[1:]:
           if round(passscore) <= score <= round(passscore+step):
               return mark
           else:
                  passscore += step
    return -1

return score2mark(score, passscore)
#+end_src

Torsten Wagner <address@hidden> writes:

> Hi,
>
> I wrote a python code block which should translate scores into marks.
> The python code seems to work. It takes two arguments. The reached score
> (out of 100) as well as how many scores where needed to pass. Starting from
> that, higher grades are calculated on a even base.
>
> I want to call the python block for each row using the sbe macro
> However, this results in an error and I can't see why
>
> | Name | ID   | 1.1 | 1.2 | 1.3 | 1.4 | 2.1 | 2.2 | 2.3 | 2.4 | 2.5 | Extra
> | Sum | Mark |
> |---------------------+------------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-------+-------+--------|
> | Name1 |     111111 |  10 |  10 |  10 |  12 |  12 |   3 |   4 |  12 |   3
> |     2 |    78 | #ERROR |
> | Name2 |     22222 |     |     |     |     |     |     |     |     |
> |       |     0 | #ERROR |
> | Name3 |     33333 |     |     |     |     |     |     |     |     |
> |       |     0 | #ERROR |
> #+TBLFM: $14='(sbe score2mark (score $13) (passscore 50))
>
> #+name: score2mark(score, passscore)
> #+begin_src python
> def score2mark(score, passscore):
>     marklist = [5, 4.3, 4, 3.7, 3.3, 3, 2.7 ,2.3, 2, 1.7, 1.3, 1]
>     step=(100-passscore)/(len(marklist)-1)
>     if  score < passscore:
>            return marklist[0]
>     for mark in marklist[1:]:
>            if round(passscore) <= score <= round(passscore+step):
>                return mark
>            else:
>                   passscore += step
>     return -1
> #+end_src
>
> Any idea what I am doing wrong? I tried different versions with
> "score2mark" some additional brackets etc. However, no luck yet.
>
> Thanks for help
>
> Torsten

-- 
Eric Schulte
http://cs.unm.edu/~eschulte